Model Answers for Section 3-2 a) B v ~A b) (A & B) v C ~A v B CM C v (A & B) CM ~A v ~~B DN, STE (C v A) & (C v B) D ~(A & ~B) DM (A v C) & (B v C) C, SLE c) A & (~~C v B) d) ~((A&~B) v (C & ~B)) A & (C v B) DN, SLE ~(A& ~B) & ~ (C & ~B) DM (A & C) v (A & B) D (~A v ~~B) & (~C v ~~B) DMx2, SLE (~A v B) & (~C v B) DN, SLE (B v ~A) & (B v ~C) CMx2, SLE B v (~A & ~C) D (~A & ~C) v B CM e) (A v B) & (C v D) ((A v B) & C) v ((A v B) & D) D (C & (A v B)) v (D & (A v B)) CMx2, SLE ((C & A) v (C & B)) v ((D & A) v (D & B)) Dx2, SLE ((A & C) v (B & C)) v ((A & D) v (B & D)) CMx4, SLE (A & C) v (B & C) v (A & D) v (B & D) A NOTE: THIS LAST STATEMENT IS AN ABBREVIATION FOR : (((A & C) v (B & C)) v (A & D)) v (B & D) f) (A & B) v (C & D) ((A & B) v C) & ((A & B) v D) D (C v (A & B)) & (D v (A & B)) CMx2, SLE ((C v A) & (C v B)) & ((D v A) & (D v B)) Dx2, SLE ((A v C) & (B v C)) & ((A v D) & (B v D)) CMx4, SLE (A v C) & (B v C) & (A v D) & (B v D) A g) ((C & A) v (B & C)) v (C & ~(~B & ~A)) ((C & A) v (C & B)) v (C & ~(~B & ~A)) CM, SLE (C & (A v B)) v (C & ~(~B & ~A)) D, SLE (C & (A v B)) v (C & (~~B v ~~A)) DM, SLE (C & (A v B)) v (C & (B v A)) DN x 2, SLE (C & (A v B)) v (C & (A v B)) CM, SLE C & (A v B) RD h) IN THE FOLLOWING PROOFS WE WORK UPSIDE DOWN, THAT IS, BEGIN WITH THE TARGET, AND WORK BACKWARDS TO THE ORIGINAL STATEMENT. C & (~A v ~(~C v A)) C & (~Av (~~C & ~A)) DM, SLE C & (~A v (C&~A)) DN, SLE (C & ~A) v (C & (C & ~A)) D (C & ~A) v ((C & C) & ~A) A, SLE (C & ~A) v (C & ~A) R, SLE C &~A R i) C & (~(Av~B) v (B & ~(~C v A))) C & ((~A & ~~B) v (B & (~~C & ~A))) DMx2, SLE C & ((~A & B) v (B & (C & ~A))) DNx2, SLE C & ((~A & B) v ((B & C) & ~A)) A, SLE (C & (~A & B)) v (C & ((B & C) & ~A)) D (C & (~A & B) v ((C & (B & C)) & ~A) A, SLE (C & (~A & B) v (((B & C) & C) & ~A) CM, SLE (C & (~A & B) v ((B & (C & C)) & ~A) A, SLE (C& (~A & B)) v ((B & C) & ~A) R, SLE ((~A & B) & C) v (~A & (B & C)) CM, SLE ((~A & B) & C) v ((~A & B) & C) A, SLE (~A & B) & C RD